Find parametric equations through point P=(2,2,7) in the direction of the vector v = (44, 14, -20)?

9514 1404 393

  (x, y, z) = (2+44t, 2+14t, 7-20t)

Step-by-step explanation:

One way to write parametric equations for line L is ...

  L = P + t·v

where P is the given point and v is the given direction vector. Using that form, we have ...

  (x, y, z) = (2+44t, 2+14t, 7-20t)

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If you like, you can remove a common factor of 2 from the coefficients of t.

  (x, y, z) = (2+22t, 2+7t, 7-10t)

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form