PLEASE HELP1!1!1! suppose one particular pyramid in egypt has a square base of side length 280 meters and a perpendicular height of 144 meters what is the surgace area of the pyramid?

Pyramid Surface Area = .5 * Perim of Base * Slant Height

Slant Height^2 = 144^2 + 140^2

Slant Height^2 = 20,736 + 19,600

Slant Height^2 = 40,336

Slant Height = 200.8382433701

Surface Area = .5 * perim of base * slant height

Surface Area = .5 * 1,200 * 200.8382433701

Surface Area = 120,503 square meters

Source = www.1728.org/volpyrmd.com

Step-by-step explanation:

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.