What is the area of the quadrilateral and what is the perimeter

Area of Trapezoid = (b1 + b2)h

                                         2

Area = (9 in + 17 in) (3 in = 1/4 ft)

                      2

A = (26 in)(3 in)/2

A = 78 in2/2

A = 39 in2

Perimeter = bi + b2 + 2l

             P = 9in + 17 in + 2(5 in)

             P = 26 in + 10 in

             P = 36 inches

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.