A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y=-16x^2+174x+78
equation

551.06feet

Step-by-step explanation:

Given the equation

y=-16x^2+174x+78

At maximum height, dy/dx = 0

dy/dx = -32x + 174

0 = -32x+174

32x = 174

x = 174/32

x = 5.4375

GEt the maximum height

y=-16x^2+174x+78

y=-16(5.4375)^2+174(5.4375)+78

y = -473.0625 + 946.125 + 78

y = 551.0625

Hence the maximum height is 551.06feet to the nearest hundredth

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12