A chemist has three different acid solutions. The first acid solution contains 15 % acid, the second contains 35 % and the third contains 65 % . He wants to use all three solutions to obtain a mixture of 48 liters containing 50 % acid, using 2 times as much of the 65 % solution as the 35 % solution. How many liters of each solution should be used?

answer: 180

step-by-step explanation:

12-2=10

20-2=18

10x18=180

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00