Classify the triangle with the given side lengths as acute, right, obtuse, or not a triangle: 9,15,19 NOT A RIGHT TRIANGLE THANKS FOR THE HELP! NO SPAMS OR LINKS PLEASE​

It is not a right triangles because 15^2 + 13^2 is NOT EQUAL to 19^2

let x, y, and z be the angles inside the triangle.

Law of cosines says:

19^2 = 13^2 + 15^2 - 2(13)(15)cos x

361 = 169 + 225 - 390 cos x

-33 = -390 cos x

-33/-390 = cos x

11/130 = cos x

x = inverse cosine (11/130)

= 85.14609471338569

Per law of sines:

sin x/19 = sin y / 13

(13/19)sinx = sin y

inverse_sine ( (13/19) sin x) = y

y = 42.9810733896016548

Per law of sines

sin x/19 = sin z / 15

z = inverse_sine( (15/19) sin x)

= 51.8728352950227805

So it is an acute triangle and yes, these angles add up to 180

acute

Step-by-step explanation:

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step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.