Question 11: A diesel train traveled to Johannesburg and back. The trip there took 6 hours and
the trip back took 9 hours. It averaged 23 miles per hour faster on the trip there
than on the return trip. Find the diesel train's average speed on the outbound (first
part traveling to Johannesburg) trip.

69 miles per hour

Step-by-step explanation:

Given

Trip to:

--- time

Trip back

Required

Determine the average speed to Johannesburg

Average speed is calculated as:

Make distance the subject

Since distance is constant, then:

This gives:

Open bracket

Collect like terms

Solve for s2

Recall that:

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: