The graph of which function has an amplitude of 3 and a right phase shift of ? y = 3+ sin 2(x - 5)
y = 3sin 2(2
y = 3+ sin 2 (2+)
y = 3sin 2(x + 5)

Option 4

Step-by-step explanation:

Equation representing the sine function is,

y = Asin[B(x- C)] + D

Here, A = Amplitude

B =

C = Phase shift

D = Vertical shift

If the amplitude of the the given function = 3 and right phase shift =

Therefore, equation of the sine function will be,

By comparing this equation with the given options,

Equation representing right phase shift = and amplitude = 3,

This equation represents right phase shift = and amplitude = 3.

Therefore, Option 4 is the correct option.

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.