The graph contains a system of equations. What two equations are represented in this system? Select all that apply. A y=-x-6
B y=2x-3
C y=-1/2x -3
D y= x-3​

what the. ok ok fine here Choose something close to (1.8,2.6)

Choice A

Step-by-step explanation:

Without the graph provided, I would prefer to do this algebraically.

y=2x-1

y=-1/4x+3

Since both are solved for y, I'm going to replace the first y with what the second y equals.

-1/4x+3=2x-1

I don't really like to deal with fractions quite yet so I'm going to multiply both sides by 4.

-1x+12=8x-4

I'm going to add 1x on both sides.

    12=9x-4

I'm going to add 4 on both sides.

    16=9x

I'm going to divide both sides by 9

   16/9=x

This is the same as saying x=16/9.

Now to find y, just choose one of the equations and replace x with 16/9.

y=2x-1

y=2(16/9)-1

y=32/9-1

y=32/9-9/9

y=(32-9)/9

y=23/9

So the exact solution is (16/9,23/9).

Round these numbers to the nearest tenths you get:

(1.8, 2.6) .

To get this I just typed into my calculator 16 divided by 9 and 23 divided by 9

16 divided by 9 gave me 1.777777777777777777777777777

23 divided by 9 gave me 2.5555555555555555555555555

So choose something close to (1.8, 2.6).

So your ordered pair (1.75,2.5) is pretty close to that so choice A.

can someone answer this question plz

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0