Find the area of the polygon with vertices P(5,-1), Q(-1,-4), R(-3,1), and S(0,3). If necessary, round to the nearest tenth.

14.3 sq units

Step-by-step explanation:

this shape is a trapezoid so we need to find height and each parallel base

to find height we can take the midpoint of RS and the midpoint of QP and then find the distance between each midpoint

midpoint of RS = (-3/2,2)

midpoint of QP = (2,-5/2)

distance between the two is 16/2 or 8

d(RS) = √2²+3² =

d(QP) = √3²+6² = √45 = or 3

put values into the formula for area:

A = 1/2(8) + ( + 3)

A = 4 + ( + 3)

A ≈ 14.3

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

answer: i guess 5 units?

step-by-step explanation: