An airplane in flight needed to make an emergency landing so it descended at an angle of depression of 15 degrees for 50000 feet until it landed. How many
feet is the vertical drop from when the plane initially began it's descent to
when it reached the ground? Round to the nearest whole number. (Hint:
draw a picture)

13,397 ft

Step-by-step explanation:

tan 15 = height/50,000

0.2679(50,000) = 13,397 ft

78.59 is the mean

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet