WILL MARK BRAINLIEST IF GOTTEN RIGHT

CE = 3

Step-by-step explanation:

Given 2 intersecting chords then the product of the parts of one chord is equal to the product of the parts of the other chord, that is

x(x + 1) = 3 × 4 = 12

x² + x = 12 ( subtract 12 from both sides )

x² + x - 12 = 0 ← in standard form

(x + 4)(x - 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 3 = 0 ⇒ x = 3

But x > 0 so x = 3

Then

CE = x = 3

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)