(x + 1)(x + 2)(x + 3)(x + 4) + x(x + 5) = 0

Step-by-step explanation:

(x−1)(x−2)(x+3)(x+4)+6=0

⟹(x−1)(x+3)(x−2)(x+4)+6=0

⟹(x2+2x−3)(x2+2x−8)+6=0

Lety=x2+2x

(x2+2x−3)(x2+2x−8)+6=0

⟹(y−3)(y−8)+6=0

⟹y2−11y+24+6=0

⟹y2−11y+30=0

⟹(y−6)(y−5)=0

⟹y=6∨y=5

y=6⟹x2+2x=6⟹x2+2x−6=0

⟹x=−2±4+24−−−−−√2=−2±27–√2

⟹x=−1±7–√

y=5⟹x2+2x=5⟹x2+2x−5=0

⟹x=−2±4+20−−−−−√2=−2±26–√2

⟹x=−1±6–√

∴−1±7–√∨−1±6–√

1/2*qr*rs

step-by-step explanation:

3 is greater then both of those numbers