. If sin (A + B) = 1 and tan (A - B) = 1/v3, find the value of:
i) tan A+ tan B
ii) sec A- cosec B
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If  sin (A + B) = 1

and tan (A - B) = 1/√3

value of:

We know that,

So,

A + B + A - B = 90 + 30

(A + A) + (B - B) = 120

2A = 120

A = 120/2

By putting value of A in 2

A - B = 30

60 - B = 30

-B = 30 - 60

-B = -30

tan 60 + tan 30

We know that

√3 + 1/√3

√3 × √3 + 1/√3

3 + 1/√3

sec A- cosec B

sec 60 - cosec 30

We know that

2 - 2 =

tan A+ tan B=4/√3

sec A- cosec B=0

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