Show that (X+1)(x+3)(x+5) can be written in the form ax^3+bx^2+cx+d

(x+1)(x+3)(x+5) = x^3 + 9 x^2 + 23 x + 15

Step-by-step explanation:

If you apply the distributive property, you can expand the expression to x^3 + 9 x^2 + 23 x + 15, from that you can see that:

a = 1

b = 9

c = 23

d = 15

And with these values, ax^3+bx^2+cx+d completely equals the given expression.

anser is a

step-by-step explanation:

negitive slope

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form