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Given P(x) = 2x3+ 3x2- x + 4, find P(0) and P(-2).

Given:

Polynomial p(x)=x⁴-2x³+3x²-ax+3a-7 which gives remainder 19 when divided by x+1

To Find:

Solution:

Dividend= x⁴-2x³+3x²-ax+3a-7

Divisor= x+1

Remainder= 19

On dividing x⁴-2x³+3x²-ax+3a-7 by x+1, we get

(Calculation in First attachment)

Remainder= 4a-1

Also, it is given that

Remainder=19

⇒ 4a-1= 19

⇒ 4a= 20

⇒ a= 5

Now, after putting value of a in dividend, we get

Dividend= x⁴-2x³+3x²-(5)x+3(5)-7

Dividend= x⁴-2x³+3x²-5x+15-7

Dividend= x⁴-2x³+3x²-5x+8

Now,

Dividend= x⁴-2x³+3x²-5x+8

Divisor= x+2

After dividing x⁴-2x³+3x²-5x+8 by x+2, we get

(Calculation in second attachment)

Remainder= 62

Hence, the value of a is 5 and required remainder is 62.Given:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: