In a storeroom, there are 30 blue balls,48 green balls, some red balls and some white balls. there are 3 times as many green balls as red balls and 5 times as many blue balls as white balls. (a) How many balls are there altogether?
(b) How many balls are left in the room if 7/10 (fraction) of the balls are taken away?
pls help me answer both

7/30

Step-by-step explanation:

We first have 7 blue and 3 red out of 10, so P(1st ball is red) = 3/10

Now, we have pulled a red ball out of the bag, leaving us with 7 blue and 2 red out of 9 total balls.Then P(2nd ball is blue) = 7/9.  Put this together, P(1st red AND 2nd blue) = 3/10⋅7/9 =7/30

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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