Find zw and z/w. Leave your answers in polar form. z = 9(cos 50*+ i sin50*)

w = 10(cos30*+ i sin30*)

What is the product?

zw = ? [cos ?* + i sin ?*]

z/w = ? [cos ?*+ i sin ?*]

(* = degree)

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

47

step-by-step explanation: