What is an equation of the line that passes through the points (6, -7) and (-6,3)?

y=-5/6x-2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-(-7))/(-6-6)

m=(3+7)/-12

m=10/-12

simplify

m=-5/6

y-y1=m(x-x1)

y-(-7)=-5/6(x-6)

y+7=-5/6x+30/6

y+7=-5/6x+5

y=-5/6x+5-7

y=-5/6x-2

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5