C(1)=56 c(n)=c(n−1)⋅ 2 1 ​ What is the 4 th term in the sequences

step-by-step explanation:

i think you should think about the question and not look online.

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629