What is the equation of a circle with endpoints of the diameter at (-8, -5) and (-4, 1) ??

(x + 6) + (y + 2)^2 = 13

Step-by-step explanation:

The centre of the circle is halfway along the diameter = (-6, -2)

r^2 = (-4 - -6)^2 + ( 1 - -2)^2 = 2^2 + 3^2 = 13

So circle equation is (x - -6)^2 + (y - -2)^2 = 13

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.

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