Find three consecutive integers whose average is 20. please show work!!

19,20,21

Step-by-step explanation:

The average is 20. The numbers can be written as: 20+a, 20 +b, 20+c, with a, b, c integers (positive and negative, but higher than - 19),with a+b+c =0.

You have to find the combination a, b, c with the smallest positive integer as its higher number.

Obviously, you start with 1, and find - 1,0,+1 as a suitable solution.

Therefore, the numbers are 20-1, 20,20+1

=> 19,20,21

4x times 5x equals 20x

20x times 1x equals 20x

15x plus 5x equals 20x

Step-by-step explanation:

hope it helps