PLEASE HELP WILL GIVE BRAINLIEST. Which of the following statments is true about the equation shown? Mark all that are true. t (x) = (x-5)^2 + 7. a
the function is quadratic
b
the function will produce a line with a positive slope when graphed
c
the function will produce a concave up parabola when graphed
d
the vertex will be at (7, -5)

a and c

Step-by-step explanation:

The equation of a quadratic in vertex form is

f(x) = a (x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

f(x) = (x - 5)² + 7 ← is in vertex form

Thus the function is quadratic → a

• If a > 0 then the grapg will open upwards

• If a < 0 then the graph will open downwards

Here a = 1 > 0 then graph will open upwards → c

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it