explain why the data collection method might cause a problem, and how randomization should be properly employed.

Today businesses and organizations are connected to their clients, customers, users, employees, vendors, and sometimes even their competitors. Data can tell a story about any of these relationships, and with this information, organizations can improve almost any aspect of their operations.

Although data can be valuable, too much information is unwieldy, and the wrong data is useless. The right data collection method can mean the difference between useful insights and time-wasting misdirection.

data collection methods

Luckily, organizations have several tools at their disposal for primary data collection. The methods range from traditional and simple, such as a face-to-face interview, to more sophisticated ways to collect and analyze data.

Here are the top six data collection methods:

Interviews

Questionnaires and surveys

Observations

Documents and records

Focus groups

Oral histories

We’ll go into more detail about each later.

Qualitative vs quantitative data collection methods

Some of the methods covered here are quantitative, dealing with something that can be counted. Others are qualitative, meaning that they consider factors other than numerical values. In general, questionnaires, surveys, and documents and records are quantitative, while interviews, focus groups, observations, and oral histories are qualitative. There can also be crossover between the two methods.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240