Ball falls so that its distance above ground can be modeled by the equation s
=
−
16
t
2
+
100
s=−16t
2
+100 , where
s
s is the distance above the ground in feet and
t
t represents time in seconds. According to this model, how many seconds does it take for the ball to hit the ground? Round to the nearest tenth if necessary.

6.25 seconds

At ground level the height of ball is 0, i.e., h=0.

Using zero product property, we get   -16t -100

= -16t + 100 + 100s

= -16(t + 6.25)  -16(ts + -6.25)

=  6.25s

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

3+x

step-by-step explanation: