A die is rolled twice. What is the probability of showing a 3 on the first roll and an even number on the second roll?

Assumption:-Dice referred here is fair six-sided dice with numbers(1,2,3,4,5,6) .

Therefore the probability of showing 3 on the first roll=probability of occurrence of 3 in(1,2,3,4,5,6) which is 1/6 since 3 appears once in 6 numbers.

Probability of odd number on the second roll = probability of occurrence of odd numbers(1,3,5) in (1,2,3,4,5,6) which is equal to 3/6 equivalent to 1/2.

Probability of complete event =probability of showing a 3 on the first roll and an odd number on the second roll.

Since the occurrence of 3 on first roll is independent of the occurrence of an odd number on the second roll, Probability of complete event =(probability of showing a 3 on the first roll) x (probability of an odd number on the second roll)=1/6x1/2=1/12.

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step-by-step explanation:

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints