The symbol 3! means 3x2x1 which equals 6. Similarly, 5! means 5x4x3x2x1, which equals 120, and so on. Suppose that N! ends in exactly 3 zeros after fully multiplying out. What is the smallest value that N can have? PLS EXLPLAIN AND HELP

15

Step-by-step explanation:

1! = 1, which contains no zeroes at the end

5! = 120, which contains 1 zero at the end

10! = 3628800, which contains 2 zeroes at the end

15! = 1307674368000, which contains 3 zeroes at the end

Therefore, the smallest value that N can have is 15

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .