A random sample of 500 women and 500 men who eamed degrees in science and engineering (S&E) were asked if they work In an S&E occupation. The results of the survey are shown.

S&E Occupations Non-S&E Occupations Total

Women

76

424

500

Men

169

331

500

Total

245

755

1000

A person from the survey is randomly selected. What is the probability of each event below?

Drag tiles to the empty boxes to create your answers.

• The probability that a randomly selected person works in an S&E occupation is

• The probability that a randomly selected person is a woman and works in an S&E occupation is

• The probability that a randomly selected person is a woman or works in an S&E occupation is

76

245

500

669

745

0.245 ; 0.76 ; 0.669  

Step-by-step explanation:

  Occupations                 S&E      Non S &E       Total {Gender wise}

  Women                           76             424               500

 Men                                 169            331               500

Total {occupation wise}      245            755             1000 [Grand Total]

1) Probability (any person in S & E) = Total people in S & E / Total people = 245 / 1000 = 0.245

2) Prob (woman & works in S & E) , ie P (W ⋂ S) =  Total women in S & E / Total people  =  76 /  100 = 0.76

3) Prob (woman or works in S & E), ie P (W U S) = P( Women) + P (S & E) - Prob (Women & SE), ie P (W) + P (S &E) - P (W ⋂ S) = ( 500 + 245 - 76 ) / 1000 = 669 / 1000 = 0.669

$35.59 in pounds

step-by-step explanation:

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

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