A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. y=-16x^2+124x+127

Step-by-step explanation:

so when the height is zero, that's when the rocket hits the ground.  The equation will have two zeros,  but one would be for a negative time,  or before the rocket is launched.    so we only one the one after the rocket is launched.

use the quadratic formula to solve for  x  ( which is time)

-124 +- sqrt [ - 4*(-16)*(127) ] / 2 (-16)

-124 +- sqrt [15376 + 8128 ] / -32

-124 +- sqrt [23504 ] / -32

-124 +- 153.310 / -32

if we take the positive part it will become the negative time so skip that one try the negative part 1st

-124 - 153.310 / -32

-277.310 / -32

8.6659 seconds to hit the ground.    ( time of flight)  aka   TOF

8.67 seconds  ( rounded to nearest 100th)

34

step-by-step explanation:

a. (14,375+570)(5.3) b. 158,417$

step-by-step explanation:

a. you are basically just setting up the equation. f= amount of debt hence 14,375. g= how much she is borrowing from her parents weekly hence 570 and t= the interest on her debt. creating the equation.

b.   14,375+570= 14,945

      14,945 x 5.3 = 79,208.5

      79,208.5 x 2(years) = 158,417(answer)