Amal designed a silver necklace pendant in the shape of a cone. The slant height of the cone is 5 millimeters, and the radius of the cone is 3 millimeters. What is the volume of the silver pendant, rounded to the nearest tenth?

Use 3.14 for π.

37.7 mm³

Step-by-step explanation:

Step 1

We find the height of the cone

we are given slant height = 5mm and radius = 3mm

Height = √l² - r²

Where l = Slant height

Hence

h = √5² - 3²

h = √25 - 9

h = √16

h = 4

Hence, the height of the cone = 4mm

Step 2

We can proceed to calculate the volume of the cone

Volume = 1/3 πr²h

π = 3.14

Hence,

Volume = 1/3 × 3.14 × 3² × 4

= 37.68 mm³

Approximately, Volume of the cone to the nearest tenth = 37.7 mm³

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !