The area of the rectangle is 40% larger than the area of the triangle. What is the length ,L, of the rectangle?

10 units

Step-by-step explanation:

Area of the triangle (A') = 1/2bh

A' = 1/2bh............ Equation 1

Where b = base of the triangle, h = height of the triangle

From the diagram,

Given: b = 12.5 unit, h = 4 unit

Substitute into equation 1

A' = 1/2(12.5)(4)

A' = 25 squared unit.

Also,

Area of the rectangle (A) = Lenght(L)×width(w)

A = Lw............ Equation 2

From the question,

If the area of the rectangle is 40% larger than the area of the triangle

Therefore,

A = 1.4A'

A = 1.4(25)

A = 35 squared unit.

Also given: w = 3 = 7/2

Substitute into equation 2

35 = L×7/2

7L = 35×2

7L = 70

L = 70/7

L = 10 units

50- 250 is correct i did that one too

step-by-step explanation:

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,