Find the surface area of the pyramid. The side lengths of the base are equal.

8 x 6.9 x 1/2(basically just dividing by 2) 27.6 area of the base.

8 x 10 = 80, 80 divided by 2 = 40, 40 x 2(area of two triangles) = 80 area of two triangles on the side

8 x 10 = 80, 80 divided by 2 ( x 1/2) = 40 triangle area behind

Add all the given areas:

27.6 + 80 + 40 = 147.6 m^2 is your surface area.

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

squares, rhombus, rectangles