Jeff has 4 red pens and 2 blue pens in his backpack. He also has 3 yellow highlighters and 2 green highlighters in his backpack. If he reaches into his backpack and grabs one pen and one highlighter without looking, what is the probability that he will grab a red pen and a yellow highlighter?

1/15

Step-by-step explanation:

In probability,

"AND" means "multiplication"

"OR" means "ADDITION"

We want probability of Blue Pen and Yellow Highlighter. So we find individual probabilities and "MULTIPLY" them.

Let P(b) be probability of blue pen

Let P(y) be probability of yellow highlighter

We know probability of event is that event divided by total number of that

So,

There are 4 + 2 = 6 pens

Blue pen = 2

Hence,

P(b) = 2/6 = 1/3

And,

There are 5 highlighters

Yellow highlighter = 1

Hence,

P(y) = 1/5

Now,

P(b and y) = 1/3 * 1/5 = 1/15

Hence,

probability of grabbing blue pen and a yellow highlighter is  1/15

the answer is 375 miles

step-by-step explanation: