![\displaystyle b(x-3) \geq ax+7b\\\\bx -3b\geq ax+7b\\\\Subtract \ ax \ to \ both \ sides\\\\bx-ax-3b\geq 7b\\\\Add \ 3b \ to \ both \ sides\\\\bx-ax \geq 7b+3b\\\\x(b-a) \geq 10b\\\\Divide \ (b-a) \ to \ both \ sides\\\\x \geq \frac{10b}{b-a} \\\\\rule[225]{225}{2}](/tpl/images/2363/1606/1f945.png)
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Mathematics, 19.05.2021 14:00 khohenfeld0
Need help with this question I would appreciate it.​
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