6. AB and BC are both tangents to the circle centre O (left). If OA = 5 cm and AB = 12 cm calculate:
a) the size of angle OAB,
b) the length OB.
7. If OA is a radius of the circle (below) and PB the tangent to
the circle at A, calculate angle ABO.

a) The size of angle OAB is 90°.

b) The length of O is 13cm.

7. Angle ABO is 28°.

Step-by-step explanation:

A) It is a right angle.

B) Since A is a right angle I can use the Pythagorean Theorem.

144+ 25=

x=13

7) Since Angle OAB is a right angle and all interior angles of a shape equal 180° I added 90 and 62 and subtracted the sum by 180.

90+62=152

180-152=28

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length