To approach the runway, a pilot of a small plane must begin at 6 degrees, descent starting from a height of 1905 feet above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach

C. 3.5 mi

Step-by-step explanation:

Reference angle = angle of elevation

Angle of elevation = angle of depression = 6° (alternate angle theorem)

Hypotenuse = x

Opposite = 1905 ft

Apply trigonometric function SOH:

Sin 6° = Opp/Hyp

Sin 6° = 1905/x

x * Sin 6° = 1905

x = 1905/Sin 6°

x = 18,224.7 ft

Convert form feet to miles

1 mi = 5,280 ft

Therefore,

18,224.7 = 18,224.7/5,280

= 3.45164773 mi

≈ 3.5 mi (nearest mile)

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d

it's d

step-by-step explanation: