100 points! Need help! 1: At what point(s) do these graphs intersect?
y=x^2+4x+3
y=4x+12

Seth’s solution:
y=x^2+4x+3
y=4x+12
x^2+4x+3=4x+12
x^2-9=0
x^2=9
x=3
The graphs intersect at .
Is Seth’s solution correct? Explain.

2: A rocket is launched vertically from the ground with an initial velocity of 48 .
(a) Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched.
(b) Graph on the coordinate plane.
(c) Use your graph from Part b to determine the rocket’s maximum height, the amount of time it took to reach its maximum height, and the amount of time it was in the air.

c

step-by-step explanation:

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

283 square feet

step-by-step explanation:

good luck

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )