A bag contains 6 red marbles, 6 green marbles, and 6 blue marbles. If Olivia draws a marble, replaced it and then draws another marble, what is the probability that both marbles she draws will be red?

5/51 or 9.8

Step-by-step explanation:

Since she does not put the marble back it's dependent.

1/3 chances the first marble is red and 5/17 the second is too.

Multiply and you get 5/51 odds, or approximately 9.8% chance

1/9.

Step-by-step explanation:

Prob(First marble is red) = 6/18 = 1/3

Prob(Second marble is red) = 1/3

Required probability = 1/3 * 1/3 = 1/9.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: none of these answers are correct only the second half is

step-by-step explanation: