which equation describes the line that passes through the point (1,6) and is parallel to the line 2x + y =3

Step-by-step explanation:Parallel Lines have the SAME SLOPE

We first Find the Slope of the line

y

=

2

x

+

3

The Slope Intercept Form of the equation of a given line is:

y

=

m

x

+

c

where

m

is the Slope of that line, and

c

is the Y intercept.

For this line, the Slope is

2

So the Slope of the line PARALLEL to

y

=

2

x

+

3

will also be

2

. And we are given that it passes through the point

(

−

3

,

4

)

With this, we can use the Point Slope form to find the equation of the line.

The Point-Slope form of the Equation of a Straight Line is:

(

y

−

k

)

=

m

⋅

(

x

−

h

)

m

is the Slope of the Line

(

h

,

k

)

are the co-ordinates of any point on that Line.

Here, we have been given the coordinates

(

h

,

k

)

of 1 point on that line as

(

−

3

,

4

)

And the Slope

m

is

2

Substituting the values of

h

,

k

and

m

in the Point-Slope form, we get

(

y

−

4

)

=

(

2

)

⋅

(

x

−

(

−

3

)

)

The above will be the Equation of the Line in Point-Slope form.

If we need it in the Slope Intercept Form, we need to follow these steps:

Modifying the equation, we get:

(

y

−

4

)

=

2

⋅

(

x

+

3

)

y

−

4

=

2

x

+

6

y

=

2

x

+

6

+

4

We get the equation of the line as :

y

=

2

x

+

10

The graph will look like this:

graph{y=2x+10 [-10, 10, -5, 5]}

easy math just plug in a and b

step-by-step explanation: