Mathematics, 18.05.2021 19:10 chanthonymjones

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 4X2)/8. Determine the bias and the mean squared error for this estimator of the mean. Bias: Mean Square Error:

Answers: 1

Show answers

Answers

Answer from: maddie53116

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= 6.3175 + 0.3136

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

Answer from: Quest

fahrenheit

step-by-step explanation:

fahrenheit is more precise than celsius. the ambient temperature on most of the inhabited world ranges from -20 degrees fahrenheit to 110 degrees fahrenheit—a 130-degree range. on the celsius scale, that range is from -28.8 degrees to 43.3 degrees—a 72.1-degree range. this means that you can get a more exact measurement of the air temperature using fahrenheit because it uses almost twice the scale.

Answer from: Quest

no this is a nonlinear negative

Will give is this a strong positive linear association or something else?

Another question on Mathematics

Mathematics, 21.06.2019 15:30

On the first of each month, shelly runs a 5k race. she keeps track of her times to track her progress. her time in minutes is recorded in the table: jan 40.55 july 35.38 feb 41.51 aug 37.48 mar 42.01 sept 40.87 apr 38.76 oct 48.32 may 36.32 nov 41.59 june 34.28 dec 42.71 determine the difference between the mean of the data, including the outlier and excluding the outlier. round to the hundredths place. 39.98 39.22 0.76 1.21

Answers: 1

Answer

Mathematics, 21.06.2019 16:00

()1. how do you find range? 2.the following set of data is to be organized into a histogram. if there are to be five intervals on the graph, what should the length of each interval be? 30, 34, 23, 21, 27, 25, 29, 29, 25, 23, 32, 31

Answers: 1

Answer

Mathematics, 21.06.2019 18:10

Abc will undergo two transformations to give aa'b'c' which pair of transformations will give a different image of aabc if the order of the transformations is reversed? a. a rotation 90' counterclockwise about the origin followed by a reflection across the y-axis b a translation 5 units down followed by a translation 4 units to the right c. a reflection across the x-axis followed by a reflection across the y-axis a rotation 180'clockwise about the ongin followed by a reflection across the y-axis reset next 2 omentum all rights reserved o atk me anything o o e

Answers: 1

Answer

Mathematics, 21.06.2019 19:00

The quadratic function h(t)=-16.1t^2+150 choose the graph representation

Answers: 1

Answer

You know the right answer?

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get tw...

Questions

Mathematics, 10.11.2020 04:50

What is 68*456*4*54*65*65*34*96*0*678*353*6 7*98*54*5...

Mathematics, 10.11.2020 04:50