Please help me with geometry !! Been stuck a while

area of circle having radius 3

is πr²=π*3²=9π square units

area of circle having radius 2

=πr²=π×2²=4π square units

again

area of big circle having radius [3+2]=5 units

=πr²=π×5²=25π square units

Now

area of shaded region=25π-4π-9π=12π or 37.7square units.

37.7 sq units

Step-by-step explanation:

Find area if entire region then subtract out each smaller circle

Diameter of entire circle would be 3(2)+2(2) which is 10 so radius is 5

Area of entire region = 25π

Area of circle one = 9π

Area of circle two = 4π

Area of shaded region = 25π - 13π which is 12π or 37.7

da freeck kinda math is this just drop out

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.