The picture below shows a box sliding down a ramp: A right triangle ABC has measure of angle ABC equal to 90 degrees and measure of angle ACB equal to 62 degrees. The length of A

What is the distance, in feet, that the box has to travel to move from point A to point C? (5 points)

10 divided by cot 62 degrees
10 cosec 62°
10 divided by sec 62 degrees
10 sin 62°

eve and marks ratios are equivalent

step-by-step explanation:

b

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

step-by-step explanation:

im not sure what the answer is