What is the strongest classification of the figure formed by the following points? (–10,-4), (-7,-8), (-5,-4), (-2,-8)
OA. Paralellogram
OB. Quadrilateral
OC. Rectangle
OD. Rhombus

A. Parallelogram

Step-by-step explanation:

The given points are;

(-10, -4), (-7, -8), (-5, -4), (-2, -8)

Let 'A' represent the point (-10, -4), let 'B' represent the point (-7, -8), let 'C' represent the point (-5, -4), and let 'D' represent the point (-2, -8), we have;

The (horizontal) distance between points A and C = -5 - (-10) = 5

The (horizontal) distance between points B and D = -2 - (-7) = 5

Therefore;

The length of = The length of

The length of = √((-10 - (-7))² + (-4 - (-8))²)) = 5

The length of = √((-5 - (-2))² + (-4 - (-8))²)) = 5

∴ The length of = The length of

is parallel to the horizontal axis

is parallel to the horizontal axis

∴ ║

Given that = , then ║

Therefore, the quadrilateral ABCD is a parallelogram

(The angle ∠ABD = 180 - arctan (4/3) ≈ 126.9 > 90, therefore, the parallelogram ABCD is not a rectangle.)

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )