The coordinates of the vertices of a quadrilateral are S (3,5), N (3,-1), G(-2,-6), and X (-2,1). The figure is rotated 180° counterclockwise
with the origin as the center of rotation to create quadrilateral S'N'GX.
6
4
-6
-4
6
What are the coordinates of the vertices of quadrilateral S'N'G'X?
S=1
N = 1

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

what are the

parallel lines have the same slope. so if the green line has a slope of -4, the slope of the red line is also -4.