G(x)=3/x find g'(x) a) by using the quotient rule: b) by first rewriting the expression using exponents and then differentiating.

a) The quotient rule is:

if: f(x) = 1/g(x)

Then:

In this case, we have:

G(x) = 1/x

Then we can write this as:

G(x) = 1/h(x) with h(x) = x, and h'(x) = 1

Using the above rule we get:

G'(x) = -(1/h(x)^2)*h'(x) = -1/x^2

b) For a function like:

f(x) = x^n

we have that:

Here we can write G(x) = x^-1

Then we have n = -1

If we use the above rule, we get:

So we got the same result using both methods.

my guess is

step-by-step explanation: