Two friends have a total of 60 coins. If the first fried gives 1/4 of his coins to the second friend, they will have an equal number of coins. How many coins does the first friend have at the beginning?

The first friend has 40 coins.

Step-by-step explanation:

The statement says that the two friend have a total of 60 coins, which can be expressed as:

x+y=60 (1), where:

x is the first friend

y is the second friend

Also, the statement says that if the first friend gives 1/4 of his coins to the second friend, they will have an equal number of coins which means that if you subtract 1/4 of the coins the first friend has this would be equal to the number of coins the second friend has now, which is:

x-1/4x=y+1/4x

x-1/4x-1/4x=y

y=x-2/4x

y=x-1/2x (2)

Next, you have replace (2) in (1) and solve for x:

x+x-1/2x=60

2x-1/2x=60

3/2x=60

x=60/(3/2)

x=(60*2)/(1*3)

x=120/3

x=40

Finally, you can replace the value of x in (2) in order to find the value of y:

y=40-1/2(40)

y=40-(20)

y=20

According to this, the answer is that the first friend has 40 coins.

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