What is the probability of choosing a pair that contains ONLY cards labeled with the letters B, C, or F?

Step-by-step explanation:

Given

--- selection

Required

Probability of choosing a pair with only B, C and F

The total selection is: 36

This is calculated as thus:

--- First selection can be any of the 6 cards

--- Second selection can be any of the 6 cards [No restriction]

So, we have:

The pair of only B, C or F is:

So, the probability is:

Simplify

i really dont know

step-by-step explanation:

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents