Quadratic functions g(x) and h(x) are graphed on the same coordinate grid. The vertex of the graph of h(x) is 12 units above the vertex of the graph of g(x) . Which pair of functions could have been used to create the graphs of g(x) and h(x) h(x)=x2−18 and g(x)=x2

h(x)=x2+18 and g(x)=x2

h(x)=(x−18)2 and g(x)=x2

h(x)=(x+18)2 and g(x)=x2

a .4y4

hope this !

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3