A sample of 23 participants took part in a hearing experiment. Among other things, the absolute hearing threshold (in decibels) was measured for each participant. The 23 measurements were as follows: 25, 22, 18, 35, 37, 34, 31, 27, 24, 21, 18, 39, 36, 33, 30, 26, 23, 35, 35, 35, 32, 32, 29 Send data to calculator Draw the histogram for these data using an initial class boundary of 17.5 and a class width of 5. Note that you can add or remove classes from the figure. Label each class with its endpoints. Frequency [:lo 11:0 9 Х $ ? 0 0 0 P. 0 Absolute hearing threshold (in decibels)​

Step-by-step explanation:

A sample of 23 participants took part in a hearing experiment. Among other things, the absolute hearing threshold (in decibels) was measured for each participant. The 23 measurements were as follows: 25, 22, 18, 35, 37, 34, 31, 27, 24, 21, 18, 39, 36, 33, 30, 26, 23, 35, 35, 35, 32, 32, 29 Send data to calculator Draw the histogram for these data using an initial class boundary of 17.5 and a class width of 5. Note that you can add or remove classes from the figure. Label each class with its endpoints. Frequency [:lo 11:0 9 Х $ ? 0 0 0 P. 0 Absolute hearing threshold (in decibels)

ans 11

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !