a turtle lives in a garden and a hedgehog lives in the woods. they leave their homes at the same time walk toward each other and meet in 5 hours. the turtle walks 10 meters per hour slower than the hedgehog. if the turtle had left home 4 1/2 hours earlier than the hedgehog had left his home, the two would meet 150m from the woods. find the distance between the garden and the woods

umm im not really sure because i never had to do this

step-by-step explanation:

to be honest i don't know but i need points so

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3